Math, asked by Niishi4541, 11 months ago

2 is one of the zeroes of the polynomial p(x) = x2-6x+8

Answers

Answered by anjalitripathi1698
2

Answer:

p(x) = x^2-6x +8

Step-by-step explanation:

p(2) = (2)^2 - 6×2 + 8

= 2×2 - 12 + 8

= 4 - 4

= 0

Therefore 2 is the zero of the given equation.

Other zero of this equation is 4 .

p(4) = (4)^2 - 6 × 4 + 8

= 16 - 24 +8

=24 - 24

= 0

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