Question

2 is one of the zeroes of the polynomial p (x) = x2 - 6x + 8.
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Answer 1

Hope this helps you..

Answer 2

2 and 4 is the zeros of the polynomial.

• The given polynomial is $x^{2}-6x+8$.
• As 2 is the zero of the polynomial , the value of the polynomial at the zeros is 0.
• p(x) =  $x^{2}-6x+8$

p(2) =  $2^{2}-6(2)+8$

p(2) =  $4 - 12 + 8$ = 0

• Therefore , 2 is the zero of the polynomial .

• To find the other zeros of the polynomial we find the roots of the polynomial ,

$x^{2}-6x+8$ = 0

(x-2)(x-4) = 0

• The other root of the polynomial is 4.

• The zeros of the polynomial is 2 and 4.