2.
Is the following relation a function? Justify your answer.
R1 = {(2, 3), (1/2,0),(2,7), (-4, 6)
Answers
Answered by
8
Answer:
According to me it's not a function because 2 have two different images and we know that if any element in domain have greater than 1 image in codomain then it's not a function
Similar questions