2. It is given that the specific heat of copper is one
tenth that of water. A copper ball of 100 g at 200°C
is put into 100 cc water at 24°C. Assuming no
heat loss to the surroundings. The final
temperature of the system is
(1) 60°C
(2) 55°C
(3) 40°C
(4) 35°C
Answers
Answered by
100
Answer:
option 3 is correct
Explanation:
given Cp of copper = 1/10 * Cp of water
let T be the final temperature
100 cc of water = 100 g
heat rejected by copper =
heat absorbed by water
100*(1/10)*(200-T) = 100*(T-24)
20 - (T/10) = T-24
44 = (11*T/10)
T = 44*10/11 = 40 ℃
Answered by
33
Answer:
Explanation:
given Cp of copper = 1/10 * Cp of water
let T be the final temperature
100 cc of water = 100 g
heat rejected by copper =
heat absorbed by water
100*(1/10)*(200-T) = 100*(T-24)
20 - (T/10) = T-24
44 = (11*T/10)
T = 44*10/11 = 40 ℃
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