2.It is given that there are 6 straight lines in a
plane so that no three of them are concurrent and no two are
parallel.Then the number of poiunts of intersection among the given six
straight lines is a)6 b)12 c)15 d)3
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Since no two straight lines are parallel to each other. So all straight lines intersect with the rest of 5 lines.
Since no three of them are concurrent, all intersections are separate, and at each intersection there are exactly two straight lines meeting.
Number of intersections is = pairs of straight lines
= ⁶C₂ = 6 * 5 / 2 = 15
Since no three of them are concurrent, all intersections are separate, and at each intersection there are exactly two straight lines meeting.
Number of intersections is = pairs of straight lines
= ⁶C₂ = 6 * 5 / 2 = 15
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Answer:
Since no two straight lines are parallel to each other. So all straight lines intersect with the rest of 5 lines.
Since no three of them are concurrent, all intersections are separate, and at each intersection there are exactly two straight lines meeting.
Number of intersections is = pairs of straight lines
= ⁶C₂ = 6 * 5 / 2 = 15
Step-by-step explanation:
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