Question

2) जर x = 3 हेkx2-10x+3=0 या समीकरणाचे एक
मूळ असेल, तर 'k' ची किंमत किती ?​

Answer 1

Step-by-step explanation:

kx^2 -10 x +3=0

on putting x=3 in above equation, we get :

k × (3)^2 -10×3 +3 =0

9k -30 +3 =0

9k -27=0

9k = 27

Therefore, k= 27 ÷9 = 3. Ans.