Question

2. Joseph jogs from one end A to the other end B of a straight
300 m road in 2 minutes 30 seconds and then turns around
and jogs 100 m back to point C in another 1 minute. What are
Joseph's average speeds and velocities in jogging (a) from A to
B and (b) from A to C?​

Answer 1

Answer:

Step-by-step explanation:

From point A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed= Distance covered /Time taken = 300/150 = 2 m/s

Average velocity=   Displacement/Time taken = 300/150 = 2 m/s

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=  Distance covered/ Time Taken =  400/210

=> 1.90 m/sec

Average velocity=   Displacement / Time taken = 200/210

=> 0.95 m/sec

Mark it as BRAINLIEST.

Answer 2

Answer:

a) total distance =300m

time taken =150s

average speed =300m/150s=2m/s

b) total distance =400

time taken =210

average speed = 400m/ 210s =1.9 m/s