Question

2. Joseph jogs from one end A to the other end B of a straight
300 m road in 2 minutes 30 seconds and then turns around
and jogs 100 m back to point C in another 1 minute. What are
Joseph's average speeds and velocities in jogging (a) from A to
B and (b) from A to C?​

Answer 1

From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=

Distance covered/ time taken

= 300/150 = 2m/sec

Average velocity = Displacement/ time taken

300/150 = 2m/sec

From point A to C

Distance covered = 300 + 100 =400

Displacement = 300 - 100 = 200m

time taken = 3 min 30 sec = ( 3×60 ) + 30 = 210 sec

Avg speed = Distance covered/ time taken

= 400/210 = 1.90 m/sec

avg velocity = Displacement/time taken

= 200/210 = 0.95 m/sec

Answer 2

Hey

Here is your answer

(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150 seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m150s=2ms−1.

Pls refer to the attachment below for your better understanding.

Pls mark me brainlist

Keep smiling

Happy learning