Question

2. Joseph Jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs Joseph' (a) from A to B and (b) Irom A to C? ​

Answer 1

Answer:

From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed

$\frac{distance \: covered}{time \: taken}$

=300/150=2 m/sec

Average velocity=

$\frac{displacement}{time \: taken}$

=300/150=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=

$\frac{distance \: covered \: \: }{time \: taken}$

= 400/210 =1.90 m/sec

Average velocity=

$\frac{displacement}{time \: taken}$

= 200/210=0.95 m/sec

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