2 k + 3 m = 12 ,km=3, find the value of 4 k2+ 3 m2
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2 k + 3 m = 12 ,km=3, find the value of 4 k2+ 3 m2
B
2
−4AC=0
Hence
4(2k−3)
2
−4(5k−6)(k−2)=0
4k
2
−12k+9−(5k
2
−16k+12)=0
−k
2
+4k−3=0
Or
k
2
−4k+3=0
(k−3)(k−1)=0
Hence
k=3 and k=1
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