Question

2 की घात 5 भाग 2 की घात 3 का मान बताए​

Answer 1

Answer:

${2}^{2}$

${a}^{m} \div {a}^{n } = {a}^{m - n}$

Step-by-step explanation:

${2}^{5} \div {2}^{3} \\ = {2}^{5 - 3} \\ = { 2}^{2}$

Answer 2

Given : 2 की घात 5 भाग 2 की घात 3

2⁵  ÷ 2³

To Find :  मान

Value

Solution:

$& \text{Laws of exponents : (a , b are non zero integers }\text{. m, n are integers)} \\ & {{\text{a}}^{n}}\times {{a}^{-n}}=1\text{ or }{{\text{a}}^{n}}=\frac{1}{{{a}^{n}}} \\ & {{a}^{m}}\times {{a}^{n}}={{a}^{m+n}} \\ & \frac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}} \\ & {{\left( {{a}^{m}} \right)}^{n}}={{\left( {{a}^{n}} \right)}^{m}}={{a}^{mn}} \\ & {{a}^{m}}\times {{b}^{m}}={{\left( ab \right)}^{m}} \\ & \frac{{{a}^{n}}}{{{b}^{n}}}={{\left( \frac{a}{b} \right)}^{n}} \\ & {{a}^{0}}=1$

2⁵  ÷ 2³

= 2⁵⁻³

= 2²

= 4

or

2⁵ = 2 * 2 * 2 * 2 * 2 = 32

2³ = 2 * 2 * 2 = 8

32 ÷ 8 = 4

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