Question

2 की पावर 125 को 11 से विभाजित करने पर शेष क्या होगा solve​

Answer 1

Answer:

10

Step-by-step explanation:

we can use Fermat's Little Theorem

Here divisor 11 is a prime number and 2 is not divisible by 11

Thus as per Fermat’s little theorem

2^10 ≡ 1 (mod 11)

2^120=(2^10)^12 ≡ (1)^12 ( mod 11)

2^125 ≡ 2^5 ( mod 11)

=32 ( mod

=10

Thus remainder is 10