Question

2 ke power 0+3ke power -1* 3ke power 2​

Answer 1

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• Evaluate ${2}^{0} + {3}^{ - 1} \times {3}^{2}$

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Any number except zero when raised to the power 0 is always 1. So,

${2}^{0} + {3}^{ - 1} \times {3}^{2}$

$= 1 + {3}^{ - 1} \times {3}^{2}$

$= 1 + {3}^{ -1 + 2}$

$= 1 + {3}^{1}$

$= 1 + 3$

$= 4$

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• Answer for the problem is = 4.

Answer 2

Answer:

${2}^{0} + {3}^{ - 1} \times {3}^{2} \\ \\ = 1 + \frac{1}{3} \times 9 \\ \\ = 4$