Question

2 kg and 3 kg blocks are placed on a smooth horizontal surface and connected by spring which is unstretched initially. The blocks are imparted
velocities as shown in the figure. The spring has stiffness 30N/m
Find max extension in spring

Answer 1

Explanation:

From conservation of momentum

Initial momentum = momentum of center of mass

m1u1+m2u2=(m1+m2)Vcm

6×2−3×1=(6+3)Vcm

Vcm=1ms−1

From conservation of energy.

21m1u12+21m2u22=21kx2+21(m1+m2)Vcm2

216×22+213×12=

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