Question

2 kg F= 10 N A block of mass 2 kg is placed on a rough surface, F = 10 N is applied on the block as shown, then friction force acting on the block is (A) 40 N (B) 12 N (C) 2 N (D) 10 N

μ = 0.6​

Answer 1

Answer:

Answer:

Coefficient of friction =  

Explanation:

Given,

Mass of the block =  m = 2 kg

Force applied on the block = F = 10 N

We know that the friction force acting on the block due to the roughness of the surface and the block is equal to the multiplication of the coefficient of friction and the normal contact force between the surface and the block.

Let be the coefficient of the frictional force between the contact surface and the block.

Friction force