Question

2 kg ice at 0 °C is mixed with 8 kg of water at
20 °C. The final temperature is
(A) 10 °C
(B)0 °C
(C) None of these
(D) 20°C​

Answer 1

$.$

let, final temperature is 't'

We know, heat gained by ice =heat lost by water

[Mass of ice ×specific heat×temp diff]+[ mass×L]

=mass of water ×specific heat×temp diff.

or, [2×(0.5×1000)×(t-0)] [2×80×1000]=8× (1×1000)×(20-t)

On solving,

t =0°C.