Question

2 kg of substance receives 500 kg and undergoes a temperature change from hundred degree Celsius to 200 degree Celsius the average is specific heat of substance during the process will be

Answer 1

Answer:

☆ Given -:

$\textsf{Mass of the substance = 2 kg }$

$\textsf{Heat absorbed by the substance = 500 KJ}$

$\textsf{Final temperature = 200 °C}$

$\textsf{Initial temperature = 100 °C}$

☆ To find -:

$\:\:\:\:\:\:\:Specific\:heat\:of\:the\:substance$

☆ Taken -:

Specific heat:

$\underline{\boxed{h=m×s×(Tf-Ti)}}$

Where,

h = Heat absorbed

m = Mass of the substance

s = Specific heat

Tf = Final temperature

Ti = Initial temperature

☆ Concept -:

First make 500 Kj in j .

By multiplying 500×1000

So , total joules is 500000 j

☆ Solution -:

$:\implies{500000j=2kg×s×(200°C-100°C)}$

$:\implies{500000\:j=2\:kg×s×100°C}$

$:\implies{500000\:j=200×s}$

$:\implies{500000\:j=200s}$

$:\implies{\frac{500000j}{200}=s}$

$:\implies{2500\:j/kg°C=s}$

☆ Answer -:

So , the specific heat of the substance during the process is 2500 j/Kg°C .