Question

2 kg of substance receives 500 kj and undergoes a temp change from 100 to 200 degrre celcius the average specific heat of substance during the process will be

Answer 1

Energy Required= Mass x S.h.c x change in temperature

E=mc◇T

C= E/m◇T

E= 500000j

m= 2kg

◇T= 200-100=100°C

C=500000/2x100

C=2500j/kg°C

Answer 2

The specific heat of substance during the reaction is $1.25kJ/kg^0C$

Explanation:

To calculate the specific heat of substance during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = 500 kJ

$c$ = specific heat = ?

m = mass of substance = 2 kg

$T_{final}$ = final temperature

$T_{initial}$ = initial temperature

Now put all the given values in the above formula, we get:

$500kJ=2kg\times c\times (200)^0C$

$c=1.25kJ/kg^0C$

Thus, the specific heat of substance during the reaction is $1.25kJ/kg^0C$

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