Physics, asked by arshadsanin, 11 months ago

2 KG of water at 352 K is mixed with 2 KG of water at 302 K. Kept in a container what is the resultant temperature of this mixture?

Answers

Answered by vedangdargar007
0

heat gained by cold body =heat lost by hot body

Q=Heat energy

m=mass of water

c=Specific heat capacity

Heat lost

for convenience convert temp in Kelvin to celcius by subtracting by 273

t=final temp

t2=initial temp

Q1=mc(t2-t1)

 =2 *4200*(79-t)

heat gained

t=final temp

t1= initial temp

Q2=mc(t-t1)

=2*4200(t-49)

Q1=Q2

2*4200(79-t)=2*4200(t-49)

79-t=t-49

2t=128

t=64

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