Question

2 kg water at 80°c mixed with 4 kg water at 40°c ;find out the total temperature of the mixture​

Answer 1

Answer:

Heat gained by ice+latent heat of fusion =heat lost by water

[Mass of ice ×specific heat×temp diff.]+[ mass×L] =mass of water ×specific heat×temp diff.

[2×(0.5×1000)×(t-0)] [2×80×1000]=8×(1×1000)×(20-t)

On solving,

t =0°C. (ans.)

Answer 2

Answer:53.33 degrees Celsius

Explanation:

Using the formula

Heat loss = Heat gain

The specific heat capacity is constant because it is the same constituent.

2(80- x) = 4(x-40).

160-2x= 4x-160

160+160=4x+2x

320=6x

X=53.33degrees Celsius