Question

(2 ki power 5+2 ki power 8) *2 ki power -7​

Answer 1

Answer:

$( {2}^{5} + {2}^{8} ) \times {2}^{ - 7}$

Factorise (2^5 + 2^8)

${2}^{5} (1 + {2}^{3} ) \times {2}^{ - 7}$

$(1 + 8) \times {2}^{5 + ( - 7)}$

$9 \times {2}^{ - 2}$

$\frac{9}{ {2}^{2} }$

$\frac{9}{4}$