Question

2 L of 0.5 N NaOH solution is mixed with 1 L of
1 M KOH solution. The molarity of hydroxide ions in
the resulting solution will be
(1) 0.33 M
(2) 0.44 M
(3) 0.55 M
(4) 0.66 M
​

Answer 1

Explanation:

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Answer 2

Answer:

0.66M.

Explanation:

Since, the solution is a mixture of NaOH and KOH hence the total concentration if the mixture will be given as M1V1 + M2V2 which after substituting the values from the question we will get that 2*0.5 + 1*1 which will be 2.

Again the total volume will be given as 2+1=3 L. So, the final concentration will be given as the total mole / total volume = 2/3 = 0.66 M.