2 let a x² + (6 +2)2 +6 = 0 and n² + 5x +2=0 have a common root, where a, b, c €N then.
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Let the roots of the first and second equations are (α,4β) and (α,3β) respectively
∴ product of the roots are 4αβ=a ....(1)
and 3αβ=6⇒αβ=2
⇒a=8 . ....From eqn (1)
Therefore, the roots of the equation x2−6x+8=0 are (2,4).
Given that the other roots of the first and second equations are integers, so if α=4⇒β=21
In this case 3β is not integer.
Therefore, common root will be α=2
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