2 Let's resolve into factors (i) (a + b)²– 5a - 5b + 6
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(a + b)2-5a-5b + 6= (a + b)2-5(a + b) + 6 … (1)To resolve it into factors we first resolve 66=2×3We know, x2 + (p + q)x + pq=(x + p)(x + q) … (2)Comparing 1 and 2p + q = -5= - 3 -2pq = 6= -3 × -2∴ (1) can be written as(a + b)2 – 3(a + b) - 2(a + b) + 6(a + b) { a + b – 3} – 2 { a + b -3}=[{a + b- 2}{a + b - 3}]∴ the resolved factors are [{a + b- 2}{a + b - 3}]
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