2. Let some elements of A x B are (1,3),(2,4) and
n(Ax B)=13. Is this possible ?why?
Answers
SOLUTION :-
GIVEN :-
Let some elements of A×B are (1,3),(2,4) and n(A×B)=13
TO CHECK
IS this possible?Why?
CONCEPT TO BE IMPLEMENTED
Let A & B are two non empty sets then their cartesian product is denoted by A × B and defined as
A × B = { (a, b) : a ∈ A & b ∈ B }
EVALUATION
Here it is given that some elements of A × B are (1,3),(2,4)
So two of all elements of A are 1 , 2
Similarly two of all elements of B are 3 , 4
So the minimum number of elements of both sets A & B are 2
Again it is given that n(A×B)=13
∴ n(A) × n(B) = 13
Since 13 is prime
So either n(A) = 1 & n(B) = 13 or n(A) = 13 & n(B) = 1
Which contradicts that the minimum number of elements of both sets A & B are 2
Hence the given statement is impossible
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Learn more from Brainly :-
If n(A) = 300, n(A∪B) = 500, n(A∩B) = 50 and n(B′) = 350, find n(B) and n(U).
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2. If A, B and C are any three sets
then prove the following using venn-diagram
A∩(BUC) = (A∩B) U (A∩C)
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Solution ⤵️
Given ⤵️
Let some elements of A×B are (1,3),(2,4) and n(A×B)=13
To Find ⤵️
Is this possible?Why?
Concept to be used here ⤵️
Let A & B are two non empty sets then their cartesian product is denoted by A × B and defined as:-
A × B = { (a, b) : a ∈ A & b ∈ B }
Calculation ⤵️
Here it is given that some elements of A × B are (1,3),(2,4)
So two of all elements of A are 1 , 2
Similarly two of all elements of B are 3 , 4
So the minimum number of elements of both sets A & B are 2
Again it is given that n(A×B)=13
∴ n(A) × n(B) = 13
Since 13 is prime
Therefore, either n(A) = 1 & n(B) = 13 or n(A) = 13 & n(B) = 1
Which contradicts that the minimum number of elements of both sets A & B are 2.
Therefore the given statement is impossible.
━━━━━━━━━━━━━━━━
Hope it helps !!
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