Question

2)lf 78 calories of heat is supplied to
15 gm of water what is the rise in
temperature if specific heat capacity
of water = 1 cal/gm C*
5.2 C
O 4C
O 9C​

Answer 1

Answer:

Let, L

Let, L f

Let, L f

Let, L f = Latent Heat of fusion,

Let, L f = Latent Heat of fusion, L

Let, L f = Latent Heat of fusion, L v

Let, L f = Latent Heat of fusion, L v

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization,

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in Temperature

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f =8000cal

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f =8000calTo convert 100g water at 273K to 100g water at 373K:

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f =8000calTo convert 100g water at 273K to 100g water at 373K: Heat required =msdθ=100×1×100=10000cal

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f =8000calTo convert 100g water at 273K to 100g water at 373K: Heat required =msdθ=100×1×100=10000calTo convert 100g water at 373K to steam at 373K, heat required = mL

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f =8000calTo convert 100g water at 273K to 100g water at 373K: Heat required =msdθ=100×1×100=10000calTo convert 100g water at 373K to steam at 373K, heat required = mL v

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f =8000calTo convert 100g water at 273K to 100g water at 373K: Heat required =msdθ=100×1×100=10000calTo convert 100g water at 373K to steam at 373K, heat required = mL v

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f =8000calTo convert 100g water at 273K to 100g water at 373K: Heat required =msdθ=100×1×100=10000calTo convert 100g water at 373K to steam at 373K, heat required = mL v =54000cal

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f =8000calTo convert 100g water at 273K to 100g water at 373K: Heat required =msdθ=100×1×100=10000calTo convert 100g water at 373K to steam at 373K, heat required = mL v =54000calThus, total heat required to convert 100g ice at 273K to 100g water at 373K is 8000+10000=18000cal

Let, L f = Latent Heat of fusion, L v = Latent Heat of Vaporization, s= specific heat, and dθ= change in TemperatureTo melt 100g ice at 273K, heat required =mL f =8000calTo convert 100g water at 273K to 100g water at 373K: Heat required =msdθ=100×1×100=10000calTo convert 100g water at 373K to steam at 373K, heat required = mL v =54000calThus, total heat required to convert 100g ice at 273K to 100g water at 373K is 8000+10000=18000calBut to convert the same quantity of ice to steam at 373K, heat required will be 72000cal

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Answer 2

Answer:

5.2 c is your answer of this ques