2. Limestone dissolves in hydrochloric acid for form calcium chloride, carbon dioxide, and water. How many moles of HCl are required to dissolve 205g of limestone? How many moles of water are formed? Note: Do not copy phase other people answer, write or type down the answer or solution step by step and explain why
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ANSWER
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2.
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2. 2.5g? g
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2. 2.5g? g Mass of CaCO3= 40+12+3(16)=52+ 48= 100.
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2. 2.5g? g Mass of CaCO3= 40+12+3(16)=52+ 48= 100. Molar mass of CaCO3=100g.
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2. 2.5g? g Mass of CaCO3= 40+12+3(16)=52+ 48= 100. Molar mass of CaCO3=100g. Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111.
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2. 2.5g? g Mass of CaCO3= 40+12+3(16)=52+ 48= 100. Molar mass of CaCO3=100g. Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111. Molar mass of CaCl2=111g.
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2. 2.5g? g Mass of CaCO3= 40+12+3(16)=52+ 48= 100. Molar mass of CaCO3=100g. Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111. Molar mass of CaCl2=111g. Mass of CaCO3 (g) Mass of CaCl2 (g)
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2. 2.5g? g Mass of CaCO3= 40+12+3(16)=52+ 48= 100. Molar mass of CaCO3=100g. Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111. Molar mass of CaCl2=111g. Mass of CaCO3 (g) Mass of CaCl2 (g) For 100g of CaCO3, 111g of CaCl_2$$ is formed.
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2. 2.5g? g Mass of CaCO3= 40+12+3(16)=52+ 48= 100. Molar mass of CaCO3=100g. Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111. Molar mass of CaCl2=111g. Mass of CaCO3 (g) Mass of CaCl2 (g) For 100g of CaCO3, 111g of CaCl_2$$ is formed.let for 2.5g of CaCO3, x g of CaCl2 is formed.
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2. 2.5g? g Mass of CaCO3= 40+12+3(16)=52+ 48= 100. Molar mass of CaCO3=100g. Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111. Molar mass of CaCl2=111g. Mass of CaCO3 (g) Mass of CaCl2 (g) For 100g of CaCO3, 111g of CaCl_2$$ is formed.let for 2.5g of CaCO3, x g of CaCl2 is formed.Thus, by cross multiplication,
ANSWERCaCO3 + 2HCl -----> CaCl2 + H2O + CO2. 2.5g? g Mass of CaCO3= 40+12+3(16)=52+ 48= 100. Molar mass of CaCO3=100g. Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111. Molar mass of CaCl2=111g. Mass of CaCO3 (g) Mass of CaCl2 (g) For 100g of CaCO3, 111g of CaCl_2$$ is formed.let for 2.5g of CaCO3, x g of CaCl2 is formed.Thus, by cross multiplication,x=111×2.5/100=2.775g=2.78g.