Question

2. Lines AB and CD are parallel. MN intersects AB and CD at points P and Q, respectively. Find the
value of ZBPQ, ZPQD and ZPQC.
M
(6x + 35)
A
B
Р P.
(4x + 15)
Q
D
N​

Answer 1

its your answer

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Answer 2

GIVEN:

AB&CD Parallel

MN intersects at P Q.

GIVEN angles:

BPQ=6x+35

PQD=4x+15

NOW:

BPQ=PQD=180

6x+35+4x+15=180(interior angles 180)

10x+40=180

10x=180-40

10x=140

x=140/10

x=14

BPQ:

6×14+35=119

PQD:

4×14+15=71

PQC:

BPQ=PQC=119 (ALTERNATE INTERIOR ANGLES ARE =)

Therefore,PQC=119

thank me❤ mark ...