2 lines passing through the point (2,3)intersects each other at an angle of 60 degree if slope of one line is 2, find equation of other line
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L1 : (y - 3)/(x-2) = 2, or y = 2 x - 1
L2 : (y - 3)/(x-2) = m. ie., y = m x - (2m-3)
Ф = angle between the lines = 60°.
Tan Ф = (2 - m)/[1 + 2 m]
(2√3 + 1) m = 2 - √3
m = (2 -√3)(2√3 -1)/11 = (5√3-8)/11
Equation of the 2nd line is:
11 y = (5√3 - 8) x + 33 - 2(5√3 - 8)
11 y = (5√3 - 8) x + 49 - 10 √3
L2 : (y - 3)/(x-2) = m. ie., y = m x - (2m-3)
Ф = angle between the lines = 60°.
Tan Ф = (2 - m)/[1 + 2 m]
(2√3 + 1) m = 2 - √3
m = (2 -√3)(2√3 -1)/11 = (5√3-8)/11
Equation of the 2nd line is:
11 y = (5√3 - 8) x + 33 - 2(5√3 - 8)
11 y = (5√3 - 8) x + 49 - 10 √3
kvnmurty:
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Answer:
Step-by-step explanation:
L1 : (y - 3)/(x-2) = 2, or y = 2 x - 1
L2 : (y - 3)/(x-2) = m. ie., y = m x - (2m-3)
Ф = angle between the lines = 60°.
Tan Ф = (2 - m)/[1 + 2 m]
(2√3 + 1) m = 2 - √3
m = (2 -√3)(2√3 -1)/11 = (5√3-8)/11
Equation of the 2nd line is:
11 y = (5√3 - 8) x + 33 - 2(5√3 - 8)
11 y = (5√3 - 8) x + 49 - 10 √3
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