Question

2 liq a and b form an ideakvsoln the vapour pressesure having 1 mole a and 3 mole b is 500 mm hg. At the same temp if one mole of b is added the vapour pressure increades by 10 mm hg . Determine their vapour pressure in pure state

Answer 1

Please find below the solution to the asked query:

Total pressure PT = PoxXx+ PoyXy

where = Xx = mole fraction of X

Xy = mole fraction of Y

Pox = pure vapour pressure of X

Poy = pure vapour pressure of Y

PT = pressure of the total mixture

First condition =

500=Pox[11+3] + Poy[31+3]

500 = Pox4+3Poy42000 =Pox + 3Poy

Second condition

600 = Pox[11+4] +Poy[41+4]

600 =Pox5+4Poy53000 = Pox + 4Poy

So we get two equations as

2000 = Pox + 3Poy

3000 = Pox +4Poy

Subtracting

-1000 = -Poy

Poy = 1000 mm Hg

Pox = -1000 mm Hg

Hope this information will clear your doubts about the topic.

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