2 litre of n2 and 2litre of h2 on complete reaction would give
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Explanation:
Given :
Volume of N2 = 2 L
Volume of H2 = 2 L
To find :
Volume of NH3 formed = ?
Solution :
N2 + 3H2 →2NH3N2 + 3H2 →2NH3
From the reaction it can be seen clearly that 1 volume of N2 is required to react with 3 volume of H2 to give 2 volumes of NH3
1 volume of N2 react with 3 volume of H2
2 L of N2 react with 3××2 L of H2 = 6 L of H2
But we only have 2 L of H2.
Therefore, H2 is the limiting reagent.
3 volumes of H2 produce 2 volumes of NH3
1 volume of H2 produce 2323 volume of NH3
2 L of H2 produce 2×232×23 L of NH3 = 1.33 L of NH3
Therefore, 1.33 L of NH3 is formed.
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