2 litres of gas is inclosed in a vessel at a pressure of 760mmHg . if temperature remain contant calculate pressure when volume change to 4 dm3
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Answer:
Explanation:
By boyle's law
when temparature is constant..
P1V1=P2V2
P1=760mm of Hg
V1=2L
V2=4dm^3= 4L (1dm^3=1L)
P2=(P1V1)/V2
=760*2/4
=380
P2=380mm of Hg=0.5atm
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