2 log 11/13+log 130/77-log 55/91=?pls ans
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Step-by-step explanation:
Given :-
2 log 11/13+log 130/77-log 55/91
To find:-
Find the value of the expression ?
Solution :-
Given that
2 log 11/13+log 130/77-log 55/91
=> 2log (11/13)+log (130/77)-log (55/91)
We know that
log a/b = log a - log b
=> 2(log 11-log 13)+(log 130-log 77)
- (log 55-log 91)
=>2log 11-2log 13 + log (2×5×13)- log (7×11)
- log (5×11) - log (7×13)
We know that
log ab = log a + log b
=> 2log 11 -2log 13 + log 2+ log 5+ log 13 - log 7 - log 11 - log 5 - log 11 + log 7 + log 13
=> (2 log 11 - 2 log 11)+(-2 log 13 + 2 log 13) + (log 7 - log 7 )+ log 2
=> 0+0+0+log 2
=> log 2
Answer:-
The value of the given expression is log 2
Used formulae:-
→ log a/b = log a - log b
→ log ab = log a + log b
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