Math, asked by dusaaishwarya6, 19 days ago

2 log 11/13+log 130/77-log 55/91=?​pls ans​

Answers

Answered by tennetiraj86
5

Step-by-step explanation:

Given :-

2 log 11/13+log 130/77-log 55/91

To find:-

Find the value of the expression ?

Solution :-

Given that

2 log 11/13+log 130/77-log 55/91

=> 2log (11/13)+log (130/77)-log (55/91)

We know that

log a/b = log a - log b

=> 2(log 11-log 13)+(log 130-log 77)

- (log 55-log 91)

=>2log 11-2log 13 + log (2×5×13)- log (7×11)

- log (5×11) - log (7×13)

We know that

log ab = log a + log b

=> 2log 11 -2log 13 + log 2+ log 5+ log 13 - log 7 - log 11 - log 5 - log 11 + log 7 + log 13

=> (2 log 11 - 2 log 11)+(-2 log 13 + 2 log 13) + (log 7 - log 7 )+ log 2

=> 0+0+0+log 2

=> log 2

Answer:-

The value of the given expression is log 2

Used formulae:-

→ log a/b = log a - log b

→ log ab = log a + log b

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