Question

2 log (16/15)+log (25/24)-log (32/27)=?​

Answer 1

Step-by-step explanation:

$log( { \frac{16}{15} })^{2} + log( \frac{25}{24}) - log( \frac{32}{27}) \\ = log( \frac{ {16}^{2} }{ {15}^{2}} \times \frac{25}{24}) \div ( \frac{32}{27}) \\ = log( \frac{16 \times 16 \times 25}{15 \times 15 \times 24} \times \frac{27}{32}) \\ = log ( \frac{27}{3 \times 3 \times 3}) = log( \frac{27}{27}) \\ = log \: 1 = 0$