Question

2(log a+log a2 +log a3+ log a⁴+...+log an)

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

n(n+1) log a

Step-by-step explanation:

2( log a + log a² + log a³ + log a⁴ + ...... + log aⁿ)

= 2( log a + 2 log a + 3  log a + 4 log a + ...... + n  log a )

= 2( log a)(1+2+3+......+n)

= 2 *  log a *  [(n)(n+1)] /2

= n(n+1) log a