Question

2
log: (log x4) - log, (log x?))
10
2) 1​

Answer 1

Yo

we should know that

loga-logb=log(a/b)

log(x^n)=nlogx

Applying the above formulas we get

$log_{2}( \frac{log( {x}^{5.4})}{ log( {x}^{2.7} ) }) = log_{2}( \frac{5.4}{2.7} ) \\ = log_{2}(2 ) = 1$

Hope this helps