2 log x+1=log250
answer is 1.pls solve
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2logx+1 = log250
or logx²+ loge = log250. { nlogx= log(x^n)}
or log(x²× e) = log250. { logm+logn= logmn}
or x²×e = 250
or x=( 250/e)^(1/2)
or logx²+ loge = log250. { nlogx= log(x^n)}
or log(x²× e) = log250. { logm+logn= logmn}
or x²×e = 250
or x=( 250/e)^(1/2)
Soham07:
answer in my book is 1
pls dont use 'e'
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