Question

③ 2 log (x-2) + log (x-4)² = 0​

Answer 1

Answer:

x= 3+√2 and x= 3-√2

Step-by-step explanation:

2 log (x-2) + log(x-4)² = 0

=>2 log( x-2) + 2log(x-4)= 0

=> log (x-2) + log ( x-4) = 0

=> log (x-2) ( x-4) = log 1

=> (x-2)(x-4)= 1

=> x²-6x+7= 0

=> x= 3± √8/2= 3±√2

=> x= 3+√2 or x= 3-√2