2 log x-y =log x+ log y then find the value x/ y + y/x
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0
Answer:
2 log (x-y) = log x +log y
or, log (x-y)² = log xy
or, (x-y)² = xy
or, x² -2xy +y² =xy
or, (x/y) -2 + (y/x) =1 [dividing both sides with xy]
or, (x/y) + (y/x) =3
Answered by
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Answer:
3
Step-by-step explanation:
2log(x-y) =log x+log y
log (x-y)^2 = log xy
(x-y)^2= xy
x^2+y^2-2xy=xy
x^2+y^2=3xy
x/y+y/x =3
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