Question

(-2)^m+1 (-2)^4 = (-2)^6

Answer 1

Answer:

1

Step-by-step explanation:

m+1 (4) = 6

m+1 = 6-4 (since the base is same... the powers subtract during their division)

m+1 = 2

m = 2-1

m= 1

HOPE IT HELPS :-)

Answer 2

ANSWER:

Given:

• (-2)^(m+1) × (-2)^4 = (-2)^6

To find:

• Value of m

Solution:

We are given that,

$\implies (-2)^{m+1}\times(-2)^4=(-2)^6$

We know that,

$\hookrightarrow a^x\times a^y=a^{x+y}$

So,

$\implies (-2)^{m+1}\times(-2)^4=(-2)^6$

$\implies (-2)^{m+1+4}=(-2)^6$

$\implies (-2)^{m+5}=(-2)^6$

As, the bases are same we wil compare the powers.

So,

$\implies (-2)^{m+5}=(-2)^6$

$\implies m+5=6$

$\implies m=6-5$

Hence,

$\implies\bf m=1$

Therefore, value of m is 1.

More Formulae:

$\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identities}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\bf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\bf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\bf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) - B^{3}\\\\8)\bf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\9)\bf\: A^{3} - B^{3} = (A-B)(A^{2} + AB + B^{2})\\\\ \end{minipage}}$