2^m+n÷2^n-m=16,3^p÷3^n=81 and a= 2^1/2 then m=?,n=? and p=?
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m = 2, n = 2, & p = 6
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kamal710:
look 1 we have to take hcf which is8 i no this only bro
Answered by
5
2^(m+n)÷2^(m-n)=16
2^(m+n)×2^-(m-n)=16
2^m+n-m+n =16
2^2n=16
2^2n=2⁴
so..base is equal then comparing powers
2n=4
n=2
putting the value of n in above ...get the value of m similarly...
3^p÷3^n=81
3^(p-n)=3⁴
P-N=4
now from the above n=2
p=4+2=6
2^(m+n)×2^-(m-n)=16
2^m+n-m+n =16
2^2n=16
2^2n=2⁴
so..base is equal then comparing powers
2n=4
n=2
putting the value of n in above ...get the value of m similarly...
3^p÷3^n=81
3^(p-n)=3⁴
P-N=4
now from the above n=2
p=4+2=6
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