Question

2. Magnitude of kinetic energy in an orbit is equal to
(a) hlalf of the potentiai energy
(b) twice of the potential energy
(c) one fourth of the potential energy
(d) None of the above​

Answer 1

Answer:It is also noticed that potential energy is twice the magnitude of total energy. It is observed that the magnitude of total energy and the kinetic energy are equal.

The expression for the kinetic energy is done taking the basic equation of kinetic energy and substituting the value of the velocity of the electron that is derived. Again potential energy is defined basing on the very definition of electrostatic potential energy. By adding both these energies we got total energy.

It is observed that all these energies are directly proportional to Squire of the atomic number and inversely proportional to Squire of principal quantum number.

Explanation:

Answer 2

Answer:

Kinetic energy in an orbit is equal to half of the potentiai energy.

Explanation:

Here two terms are main i.e Kinetic energy and Potential energy.

We can express kinetic energy as KE

And Potential energy as PE

We know,

$KE = \frac{1}{2} \times m {v}^{2} = \frac{1}{2} \frac{z {e}^{2} }{r}$

(For Hydrogen atom)

Here $PE = - \frac{z {e}^{2} }{r}$

We know,

$TE= PE+KE$

$= \frac{ - 2 {e}^{2} }{r} + \frac{1}{2} \times \frac{2 {e}^{2} }{r} = \frac{ - 1}{2} \frac{2 {e}^{2} }{r}$

$KE:PE:TE= 1:-2:-1$

Kinetic energy in an orbit is equal to half of the potentiai energy.