Question

2
Maintain social distancing - Problem Solving
Henry decides to take a walk around the park
while maintaining social distancing. Henry
notices the park is much more crowded than
usual. As he is roaming around, he is thinking
that how many residents could fit within the park
while also maintaining a proper social distance.
20
Henry knows the park is 100 meter in length by 500 meter in width. What
is the maximum number of people who could fit in the park and maintain a
safe 6-ft social distance?​

Answer 1

Given :- Henry knows the park is 100 meter in length by 500 meter in width.

To Find :- What is the maximum number of people who could fit in the park and maintain a safe 6-ft social distance ?

Solution :-

we know that,

• 1 ft = 0.3048 m .

so,

→ 1 ft = 0.3048 m

→ 6 ft = 6 * 0.3048 = 1.8288 m .

then,

→ Number of people can stand along length by maintaining safe distance = (100/1.8288) + 1 = 54 + 1 = 55

similarly,

→ Number of people can stand along width by maintaining safe distance = (500/1.8288) + 1 = 273 + 1 = 274

therefore,

→ The maximum number of people who could fit in the park by maintaining safe distance = 55 * 274 = 15070 people (Ans.)

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Answer 2

Answer:

Given :- Henry knows the park is 100 meter in length by 500 meter in width.

To Find :- What is the maximum number of people who could fit in the park and maintain a safe 6-ft social distance ?

Solution :-

we know that,

1 ft = 0.3048 m .

so,

→ 1 ft = 0.3048 m  

→ 6 ft = 6 * 0.3048 = 1.8288 m .

then,

→ Number of people can stand along length by maintaining safe distance = (100/1.8288) + 1 = 54 + 1 = 55.

similarly,

→ Number of people can stand along width by maintaining safe distance = (500/1.8288) + 1 = 273 + 1 = 274

therefore,

→ The maximum number of people who could fit in the park by maintaining safe distance = 55 * 274 = 15070 people (Ans.)

Step-by-step explanation:

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