2 marks)
3. Find the 31st term of an
a.P. Whose 10th term is 31 and the 15th term is 66
Answers
Answered by
6
Answer:
178
Step-by-step explanation:
a10=31
a15=66
a+9d=31------1
a+14d=66------2
applying elimination on 1st and 2nd equation
we get d=7
put the value of d in 1 eqn
a+9(7)=31
a+63=31
a=-32
we have to find 31st term
a+30d=-32+30(7)
-32+210
178
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