2 mass of 5 kg and 10 kg are connected to a Pulley what will be the acceleration of the system
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Answered by
96
We know that,
acceleration (a) = Force (F)/mass(m)
Let's assume that 10kg block is moving downwards direction.
On 5kg Block :-
T - mg = ma
T - 5(10) = 5a
T - 50 = 5a........(1)
On 10kg Block :-
mg - T = ma
10(10) - T = 10a
100 - T = 10a.........(2)
From (1) and (2) :-
T - 50 = 5a..(1)
100 - T = 10a..(2)
On adding both these equation we get,
50 = 15a
a = 50/15
a = 10/3m/s²
So, acceleration is 10/3 m/s²
acceleration (a) = Force (F)/mass(m)
Let's assume that 10kg block is moving downwards direction.
On 5kg Block :-
T - mg = ma
T - 5(10) = 5a
T - 50 = 5a........(1)
On 10kg Block :-
mg - T = ma
10(10) - T = 10a
100 - T = 10a.........(2)
From (1) and (2) :-
T - 50 = 5a..(1)
100 - T = 10a..(2)
On adding both these equation we get,
50 = 15a
a = 50/15
a = 10/3m/s²
So, acceleration is 10/3 m/s²
Answered by
25
after this add.. both eqn. 1 and 2 u will get acceleration..hope u understand..
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