Physics, asked by ravindrakpurnia, 11 months ago

2×mass×speed of light =velocity√mass

veryfy this

Answers

Answered by Anonymous
1




So, that’s all you need to know that THE SPEED OF LIGHT IS THE UNIVERSAL SPEED LIMIT.

Attachments:

ravindrakpurnia: W=Fs
ravindrakpurnia: F=ma
ravindrakpurnia: Yes but e=also equal 1/2 mv^2 and e is also equal to mc ^2
ravindrakpurnia: So little bit calculation I get it
ravindrakpurnia: Yes I know it
binder73: kive
ravindrakpurnia: W=fs v^2 -u^2/2a. F=ma. W=fs =ma×v^2-u^2/2a. W=1/2m(v^2-u^2) u=0 ( object is at rest ). W=1/2 mv^2 e(k)=1/2 m^2 e=1/2 mv^2 but e is also equal to mc^2 so , mc^2 =1/2mv^2. 2/1 mc^2=mv^2. 2mc =√mv^2. 2mc=v√m.
binder73: 4628(568)928=916₹858=85.:
binder73: bye call
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