Question

2 masses of 10and 20 kg are connected by massless spring a force of 200n acts on 20kg mass . if acceleration of 10kg mass is 12m/s^2 towards right find acceleration of 20 kg msss at this instant

Answer 1

Force on 10kg mass =ma

=10×2

=20N

Free body diagram

> Kx=20N

Therefore Force on 20kg mass

=100−kx

=100−20

=80N

a2=Fm

=8020

=4m/s2

Answer 2

Answer:

Explanation:

For 10 kg block : t=ma

10.12=120

For 20kg block

F-T=ma

200-120=20a

80=20a

a=4