Question

2.
Mean of sin 90º, cosec 30° and tan45° is
A)2/3
B)1
C)4/3
D)2​

Answer 1

c. 4/3 plz plz plz plz plz mark me as brilliant

Answer 2

$\huge\boxed{\underline{\bf { \red S \green O \pink L \blue U \orange T \purple I \red O \pink N \green{..}}}}$

$\mapsto \sf Mean = \frac{ \sin90 + \csc30 + \tan45}{3}$

$\mapsto \sf Mean = \frac{1 + 2 + 1}{3}$

$\mapsto \sf Mean =\frac{4}{3}$

$\large \therefore \underline{\bf Option \:C.\: is\: correct \:answer}$