Question

2 men 3 women can do a piece of work in 10 days while 3 men 2 women can do the same work in 8 days. in how many days can 2 men 1 women do the same work​

Answer 1

Answer:

2 × 10 men + 3 × 10 women

= 3 × 8 men + 2 × 8 women

⇒ 20 men + 30 women = 24 men + 16 women

⇒ 4 men = 14 women or 2 men = 7 women

∴ 2 men + 3 women = 10 women

∴ 2 men + 1 woman = 8 women

∴ M1D1 = M2D2

⇒ 10 × 10 = 8 × D2

⇒ D2 =

25

= 12

1

days

2 2

Step-by-step explanation:

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Answer 2

so your answer is this

Lets say a man alone can repair the bridge in ‘x’ days and a woman alone in ‘y’ days. This leads us to two equations.

2/x +3/y = 1/10 and 3/x +2/y = 1/8

If we solve these simultaneous equations we get x=200/7 and y=100

So two men and 1 woman does

(2x7)/200 + 1/100 = 16/200 = 2/25th of the work.

So they will take 1/(2/25) =25/2 days or 12 and a half days.