Question

2 men and 3 women can finish a piece of work in 10 days while 4 men can do it in 10 days in how many days will 3 men and 3 women finish the work?​

Answer 1

Answer:

8 days

Step-by-step explanation:

let m=daily rate of 1 man  

10*4m=1

m=1/40

let w=daily rate of 1 woman

10(2/40+3w)=1

w=1/60

let d=number of days for 3 men and 3 women

d(3/40+3/60)=1

d=8 days

Answer 2

Hence 3 men and 3 women finish the work in 12.5 days.

Step-by-step explanation:

Given:

Let time taken by 1 men = x days

and time taken by 1 women = y days

2 men and 3 women finish a piece of work in 10 days,

⇒ 2x+3y=10                           [1]

4 men can do work in 10 days,

⇒ 4x= 10

⇒ $x=\frac{10}{4}$

⇒ $x=\frac{5}{2}$  

Putting value of x in equation 1

⇒ 2x+3y=10  

⇒ $2(\frac{5}{2} )+3y=10$

⇒  5+3y=10

⇒  3y=10-5

[tex]y=\frac{5}{3}[/tex]

Now 3 men and 3 women finish the work,

⇒ 3x+3y = $3(\frac{5}{2}) +3(\frac{5}{3})$

               = $\frac{15}{2} +5$

               = $\frac{15+10}{2}$

               = $\frac{25}{2}$

               = 12.5 days.

Hence 3 men and 3 women finish the work in 12.5 days.